Hypergeometric probability distribution: `n` draws without replacement from a
HypergeometricDistribution[n, n succ, n tot]
HypergeometricDistribution[n, ns, nt]
→ HypergeometricDistribution[n, ns, nt]Mean[HypergeometricDistribution[n, ns, nt]]
→ (n*ns)/ntMean[HypergeometricDistribution[5, 10, 50]]
→ 1